Advertisement
 
(Page 3 of 3)

A tribute to Bent Larsen

Chess

September 19, 2010|By Jack Peters

GM Anatoly Karpov (U.S.S.R.)-GM Bent Larsen (Denmark), Tilburg 1980: 1 e4 e5 2 Nf3 Nf6 The drawish Petroff Defense, but Larsen does not aim for a draw! 3 d4 Nxe4 4 Bd3 d5 5 Nxe5 Nd7 6 Qe2 Risky. Today's theory concentrates on 6 Nxd7 Bxd7 7 0-0. Nxe5 7 Bxe4 As 7 dxe5 Nc5 does not worry Black. dxe4 8 Qxe4 Be6 9 Qxe5 Also 9 dxe5 Bd5 10 Qg4 h5 11 Qh3 Qe7! gives Black fine compensation. Qd7 10 0-0 0-0-0 Black has easy development and two active Bishops. White's position is surprisingly difficult. 11 Be3 Bb4 Avoiding 11…Bd6 12 Qa5. Now Black expects 12 a3 f6 13 Qg3 Bd6. 12 Nc3?! f6 13 Qg3?! Larsen suggested 13 Qf4. Bxc3 14 bxc3 h5! 15 h4 g5! The world champion has been thoroughly outplayed. Understandably, he rejects 16 hxg5 h4 17 Qh2 h3 18 g3 fxg5 19 Bxg5 Rde8 20 f3 Qc6, when he has problems at c3, f3, and e2. But his choice leads to intolerable passivity. 16 f3 Rdg8 17 Rf2 Qc6 18 Bd2 g4 Next …Be6-d5 will take aim at g2. 19 f4 Bc4 20 d5 Else Black doubles Rooks on the e-file and invades at e2. Bxd5 21 f5 Re8 22 a3 Re4 23 Re1 Rhe8 24 Rxe4 Rxe4 25 Kh2 Qc5 26 Bf4 Re1 27 Bd2 Ra1 28 Qe3 Qd6+ Less persuasive is 28…Qxe3? 29 Bxe3 Rxa3 30 Bd4. 29 Rf4 b6 30 c4 Larsen planned to refute 30 Qe8+ Kb7 31 Qxh5 with 31…Bf3!, threatening 32…Qxd2 and 32…g3+. Bxc4 31 Qd4 Qxd4 32 Rxd4 White has no real hope of saving the game, but he can prolong it. Bb5 33 Bh6 Rxa3 34 Bg7 Bd7 35 Rf4 Not 35 Bxf6? because 35…g3+ will mate. Ra5 36 Bxf6 Bxf5 37 c3 Be6 38 Kg3 Rd5 39 Re4 Kd7 40 Be5 Rd2 41 Kf4 Rxg2 42 Kg5 After 42 Bxc7 Rf2+! 43 Kg5 (as 43 Ke3 Rf3+ 44 Kd2 Bf5 costs White more material) Rf5+ 44 Kg6 Kxc7 45 Rxe6 Rc5, Black can advance his passers. Rc2 43 Kxh5 g3 44 Bxg3 Rxc3 45 Be5 Rc4 46 Re3 Bd5 47 Ra3 Ke6 48 Bg3 Kf5! Welcoming 49 Rxa7 Rc6!, with unstoppable mate. 49 Kh6 a5 50 Kg7 Kg4 51 Kf6 a4 52 Re3 Bf3 53 Be1 Rc1 54 Re7 Kh3 55 Bd2 Rc4 56 Re3 Kg2 57 Be1 Rc1 58 Bd2 Rd1 59 Bc3 c5 60 Re7 b5 61 Be5 White can leave Black with the a-pawn and "wrong Bishop" by 61 Re5 b4 62 Rxc5 bxc3 63 Rxc3, but 63…Ra1 64 Ke5 a3 will promote the pawn anyway. a3 62 Rh7 b4 63 h5 b3 64 h6 b2 65 Rg7+ Kf2 66 Bg3+ Or 66 h7 Rh1. Ke3, White Resigns.

Advertisement
Los Angeles Times Articles
|
|
|